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Lottery to be made available for public viewing


Eleven

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With all the talk about this, I didn't want it to get lost in the around the league thread.

 

The league will make video of the lottery available for viewing.

 

http://www.thehockeynews.com/blog/nhl-will-make-video-of-draft-lottery-available-for-first-time-ever/

 

EDIT:  Also, Ken Campbell can't math.

Edited by Eleven
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Held in Toronto at Rogers Sportsnet? Really?

 

I hear the phrase, "Doth protest too much." Seems like the league knows the pre-determined result will be controversial and they are taking pains to make it look legit.

 

It will be controversial because of the stakes, but not pre-determined.

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I think when all 14 lottery teams are known, I'm going to come up with a conspiracy theory to justify each team--including the Sabres (it's an easy one)--winning the lottery.  Actually, there are three really easy ones for the Sabres.

Edited by Eleven
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I think when all 14 lottery teams are known, I'm going to come up with a conspiracy theory to justify each team--including the Sabres (it's an easy one)--winning the lottery.  Actually, there are three really easy ones for the Sabres.

This is a 1st: SS stealing an idea from GR.  Me likey. :lol:

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according the article linked above, the lottery draw is performed as follows:

 

"The way the lottery works is that it is done by a machine that has ping-pong balls which have a different digit. Four of those balls will fall down the chute to create a four-digit number. That creates a total of 1,001 different possibilities and the number of random four-digit numbers each team receives prior to the lottery is dependent upon where it finished in the standings. The team with the winning number wins the lottery and gets the first pick overall."

 

according to the NHL...

http://www.nhl.com/ice/page.htm?id=68856

"Fourteen balls, numbered 1 to 14, are placed in a lottery machine. The machine expels four balls, forming a series of numbers. The four-digit series resulting from the expulsion of the balls is matched against a probability chart that divides the possible combinations among the 14 participating clubs."

 

That said according to my math, with 14 unique numbers, picking 4 of those numbers at random (non-repeating), AND if order does NOT matter, the number of possible outcomes is 1001.   

 

So who gets McDavid if that 1 out of 1001 combination appears?   Las Vegas?  

 

And doesn't that 1/1001 chance reduce the odds for each team? ie, if BUF gets 200 combinations out of 1001, that's not 20%, that's 19.98%... so it would seem to reduce ever teams odd's by 0.02%?  While not significant, it's like hitting 0/00 in roulette, it tilts the odds just slightly in the houses favor that over the long haul the Casino's make $$$ on roulette because nobody ever puts money on 0/00. 

 

I WANT ANSWERS NHL!!!!

Edited by pi2000
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according the article linked above, the lottery draw is performed as follows:

 

"The way the lottery works is that it is done by a machine that has ping-pong balls which have a different digit. Four of those balls will fall down the chute to create a four-digit number. That creates a total of 1,001 different possibilities and the number of random four-digit numbers each team receives prior to the lottery is dependent upon where it finished in the standings. The team with the winning number wins the lottery and gets the first pick overall."

 

according to the NHL...

http://www.nhl.com/ice/page.htm?id=68856

"Fourteen balls, numbered 1 to 14, are placed in a lottery machine. The machine expels four balls, forming a series of numbers. The four-digit series resulting from the expulsion of the balls is matched against a probability chart that divides the possible combinations among the 14 participating clubs."

 

That said according to my math, with 14 unique numbers, picking 4 of those numbers at random (non-repeating), AND if order does NOT matter, the number of possible outcomes is 1001.   

 

So who gets McDavid if that 1 out of 1001 combination appears?   Las Vegas?  

 

And doesn't that 1/1001 chance reduce the odds for each team? 

 

 

See my first post.  His math is way off.  Starting with the fact that with only three balls, there would be 1,000 combinations, not 1,001, and with four, there are 10,000. 

This is a 1st: SS stealing an idea from GR.  Me likey. :lol:

 

Right?  It's about time.  Here's a preview:  the three reasons why the league will rig the lottery in Buffalo's favor...

 

1)  Buffalo is the #1 pro hockey market in the US (this is according to the Wall Street Journal and not "world according to 11").

 

2)  It extends the Buffalo market to Erie.

 

3)  It gives Ontarians (Ontarionans?  Ontarites?) an inexpensive opportunity to see him play on a regular basis.

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See my first post.  His math is way off.  Starting with the fact that with only three balls, there would be 1,000 combinations, not 1,001, and with four, there are 10,000. 

 

The math is correct.   14 balls numbered 1-14, 4 non-repeating balls selected gives 1001 possible outcomes if order of the numbers do not matter.   

 

http://www.statisticshowto.com/calculators/permutation-calculator-and-combination-calculator/ (n=14, r=4, repeat=no, order=no)

 

The issue is that if you add up all the outcomes for all the teams (200 for BUF, 135 for ARI, etc...) the total comes to 1000.  

 

So there's 1 possible outcome that no team has.  

 

Grab your pitchforks folks, we're marching to Toronto on April 18th.

Edited by pi2000
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The math is correct.   14 balls numbered 1-14, 4 non-repeating balls selected gives 1001 possible outcomes if order of the numbers do not matter.   

 

http://www.statisticshowto.com/calculators/permutation-calculator-and-combination-calculator/ (n=14, r=4, repeat=no, order=no)

 

The issue is that if you add up all the outcomes for all the teams (200 for BUF, 135 for ARI, etc...) the total comes to 1000.  

 

So there's 1 possible outcome that no team has.  

 

Grab your pitchforks folks, we're marching to Toronto on April 18th.

 

I must have missed that part of your post that explained 14 balls.  I was assuming (obv.) 10 repeating balls.  That's kind of fun to type.

 

Anyway, would the 1,001th combination be a redo, perhaps?

So was this the -1th time ever?

 I guess so.

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See my first post.  His math is way off.  Starting with the fact that with only three balls, there would be 1,000 combinations, not 1,001, and with four, there are 10,000. 

 

Right?  It's about time.  Here's a preview:  the three reasons why the league will rig the lottery in Buffalo's favor...

 

1)  Buffalo is the #1 pro hockey market in the US (this is according to the Wall Street Journal and not "world according to 11").

 

2)  It extends the Buffalo market to Erie.

 

3)  It gives Ontarians (Ontarionans?  Ontarites?) an inexpensive opportunity to see him play on a regular basis.

Well they are from Ontarada.

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according the article linked above, the lottery draw is performed as follows:

 

"The way the lottery works is that it is done by a machine that has ping-pong balls which have a different digit. Four of those balls will fall down the chute to create a four-digit number. That creates a total of 1,001 different possibilities and the number of random four-digit numbers each team receives prior to the lottery is dependent upon where it finished in the standings. The team with the winning number wins the lottery and gets the first pick overall."

 

according to the NHL...

http://www.nhl.com/ice/page.htm?id=68856

"Fourteen balls, numbered 1 to 14, are placed in a lottery machine. The machine expels four balls, forming a series of numbers. The four-digit series resulting from the expulsion of the balls is matched against a probability chart that divides the possible combinations among the 14 participating clubs."

 

That said according to my math, with 14 unique numbers, picking 4 of those numbers at random (non-repeating), AND if order does NOT matter, the number of possible outcomes is 1001.   

 

So who gets McDavid if that 1 out of 1001 combination appears?   Las Vegas?  

 

And doesn't that 1/1001 chance reduce the odds for each team? ie, if BUF gets 200 combinations out of 1001, that's not 20%, that's 19.98%... so it would seem to reduce ever teams odd's by 0.02%?  While not significant, it's like hitting 0/00 in roulette, it tilts the odds just slightly in the houses favor that over the long haul the Casino's make $$$ on roulette because nobody ever puts money on 0/00. 

 

I WANT ###### ANSWERS NHL!!!!

My head hurts!!! Was always terrible at math.

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I must have missed that part of your post that explained 14 balls.  I was assuming (obv.) 10 repeating balls.  That's kind of fun to type.

 

Anyway, would the 1,001th combination be a redo, perhaps?

 I guess so.

Obviously the 1,001st choice is marked as "commissioner's choice" :nana:

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