sodbuster

12g, 24a

Just left ye olde Strand Theatre. Disney is knocking the anthology series movies out of the park. They should dump the next trilogy and just done three more of these.

I've had dreams about the Sabres winning the cup at home. A a hundred-thousand-legged, beer and nacho fueled state of emergency marching its way to Niagara Square... I don't care what history says, I want a chance at that.

Is there any chance this means she will get more media exposure and Terry will get less? I hope so, because she seems a lot more comfortable with a mic in her face than he does.

I really want to know more about the "other job-related issues uncovered" line in the TG piece. My GUESS is that he was, in fact the leaker in the organization, and I've suspected that since I heard rumors of an affair with a local radio personality a while back. That is something that could have easily been uncovered in an inveatigation of this nature.

Man, poor Arizona. They get so close every year.

Yeah. They just replace the ball each time. Same outcome.

This. Then they sit in the room by themselves until the rest of the world is given the glorious news.

This isn't correct. They are all drawn at the same time. The two sessions of card flipping are just theatrics.

In that situation, the probability of all of those outcomes would be the same.

Because it has nothing to do with the probability of certain balls coming out of the machine. The odds of any ball coming out of the machine are the same each time, as long as they're replacing each ball that comes out or drawing each ball from different machines that have identical sets of balls in them (which is my understanding).

Absolutely. Say three teams are involved, and the drawing is only 2 single digit balls. Teams are A, B, and C. A is assigned 00-09 and 10. B is assigned 10-19 and 20. C is assigned everything else, which would be 21-99. Going into the drawing, A and B each have an 11% chance of winning, C has 88%. The first ball drawn is 1, eliminating 90 possible outcomes, of which, A posses 1, B possesses 9, and C possesses 0. A has a 10% chance. B has a 90% chance. C is SOL. Ottawa is basically team B in this situation. The Sabres are team A.

I don't think it is. From what I've read, each ball comes out of a different machine, making each draw an independent event. So the permutation 2,2,2,2 has the same probability of appearing as 1,2,3,4. Unless my exposure to statistics from the professors in the political science department at Brockport has failed me, which is entirely possible. :lol:

It's even simpler than he's making it. Each team is assigned a whole bunch of possible permutations of lottery ball numbers. As each ball comes out of the machine, that eliminates a certain number of possible permutations. By the time the last ball was coming out of the machine, Ottawa had the most assigned remaining possible outcomes.

Well, I think I like Vancouver now.

He and Eichel will have something to bond over.

How does one properly pronounce his name? Is it like pilot?

:lol: That is absurd.

Absolutely. A playoff game might be the only way to top last years Rochester meet up. I would prefer the 25th, but either night works for me.

COULD you have googled it there? Does cell service travel back in time to that neck of the woods?

Lol Rob is enjoying this "night of young guys."

You can't leave! All the plants are gonna die!

I got free tickets to the game tonight and the bobble head is the only reason I took them.

Carpe shotem.

So I just missed the best period of the season? Yeah, that sounds about right.